# One side of the triangle is 3cm longer than the other side and 5cm shorter than the third side

**One side of the triangle is 3cm longer than the other side and 5cm shorter than the third side, how many times the longest side is the shortest, if the perimeter of the triangle is 41.**

To solve this problem, we introduce the conditional variable “X”, through which we denote the side of the triangle with the average length.

Then, the smaller side of the triangle will be equal to X – 3 cm, and the large side of the triangle will be equal to X + 5 cm.

Then, based on the data of the problem, we will compose the following equation: X – 3 + X + X + 5 = 41.

Solving this equation, we get 3X + 2 = 41 or 3X = 39 or X = 13 centimeters.

Therefore, the smaller side of the triangle will be 13 – 3 = 10 cm, and the larger side of the triangle will be 13 + 5 = 18 cm.

This means that the large side is 18/10 = 1.8 times the smaller side of the triangle.

Answer: 1.8 times.